Vl 128 j 429v vl 718 j 533v vl 898. This problem has been solved.

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Solve for the voltage across the inductor at omega 1 rad sec.
Solve for the voltage across the inductor. Then the voltage across the inductor v l will have an initial value equal to the battery voltage at time t 0 or when the switch is first closed and then decays exponentially to zero as represented in the above curves. The formula which calculates the inductor voltage is v ldidt where v is the voltage across the inductor l is the inductance of the inductor and didt is the derivative of the current flowing across the inductor. All you have to know to calculate the voltage across the inductor is l the inductance of the inductor which is expressed in units henry and the derivative of the current going through the inductor.
However there is a definite mathematical relationship between voltage and current for an inductor as follows. Best answer 100 2 ratings previous question next question transcribed image text from this question. Show transcribed image text.
Inductors do not have a stable resistance as conductors do. Aside from any resistance intrinsic to an. Like a capacitor an inductors behavior is rooted in the variable of time.
To calculate the voltage across an inductor the formula is. Solve for the voltage across the inductor at omega 1 rad sec. Answer to solve for the voltage across the inductor at omega 1 radsec.

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